Question

Can anyone help me with this?

Answer 1

Answer:

(a)

$v = 10.1mL$ --- Silicon

$v = 9.0mL$ --- Tin

$v = 7.5mL$ -- Lead

(b)

$d = 1.55g/mL$ --- Silicon

$d = 5.56g/mL$ --- Tin

$d = 9.53g/mL$ --- Lead

Explanation:

Given

The attached table

Solving (a): The volume of each sample

For each element, the volume (v) is calculated as:

$v = v_f - v_i$

Where:

$v_f = Final\ Volume$

$v_i = Initial\ Volume$

So, we have:

Silicon:

$v_f = 40.1mL;\ \ \ v_i = 30.0mL$

So, we have:

$v = 40.1mL - 30.0mL$

$v = 10.1mL$

Tin:

$v_f = 29.0mL;\ \ \ v_i = 20.0mL$

So, we have:

$v = 29.0mL - 20.0mL$

$v = 9.0mL$

Lead:

$v_f = 33.5mL;\ \ \ v_i = 26.0mL$

So, we have:

$v = 33.5mL - 26.0mL$

$v = 7.5mL$

Solving (b): The density of each sample

For each element, the density (d) is calculated as:

$d = \frac{m}{v}$

Where

$m = mass$

$v = volume$

So, we have:

Silicon:

$m = 15.70g$

$v = 10.1mL$ --- calculated in (a)

Density (d):

$d = \frac{15.70g}{10.1mL}$

$d = 1.55g/mL$

Tin:

$m = 50.07g$

$v = 9.0mL$ --- calculated in (a)

Density (d):

$d = \frac{50.07g}{9.0mL}$

$d = 5.56g/mL$

Lead:

$m = 71.47g$

$v = 7.5mL$ --- calculated in (a)

Density (d):

$d = \frac{71.47g}{7.5mL}$

$d = 9.53g/mL$