The heights of adult men are normally distributed with a mean of 69 inches and a standard deviation of 2.75 inches. What percentile does a man who is 72 inches fall?

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Answer:

86.2%

Step-by-step explanation:

Given that:

Mean, m = 69 inches

Standard deviation. s = 2.75

Man who is 72 inches tall ; x = 72

Using the relation :

Zscore = (x - mean ) / standard deviation

Zscore = (72 - 69) / 2.75

Zscore = 3 / 2.75 = 1.09

Z = 1.09

P(Z < 1.09) = 0.862 (Z probability calculator)

0.862 * 100% = 86.2%

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