Question

A force of 12 N is applied to a block moving west. Another force of 26 N is being applied in the opposite direction. The block weighs 7kg. What is the net force and the acceleration?

Answer 1

Answer:

$F_{Net} = 14N$

$a = 2m/s^2$

Explanation:

Given

$Mass = 7kg$

$F_{west} = 12N$

$F_{opposite} = 26N$

Solving (a): The net force:

The force towards the west direction, will be regarded as negative while the opposite force will be regarded as positive.

So, the net force is:

$F_{Net} = -F_{west} + F_{opposite}$

Substitute values for the given forces

$F_{Net} = -12N + 26N$

$F_{Net} = 14N$

The net force is 14 N

Solving (b): Acceleration

Net force is calculated as:

$F_{Net} = Mass * Acceleration$

Substitute 7 kg for Mass and 14 N for Net force:

$14N = 7kg* a$

Make a the subject:

$a = \frac{14N}{7kg}$

$a = 2N/kg$

$a = 2m/s^2$

Hence, the acceleration is $2m/s^2$