Question

i'm really getting tired of the questions like these lol

Answer 1

Step-by-step explanation:

(3x+3)(x+2)=

3x^2+6x+3x+6

=3x^2+9x+6

we get quadratic equation

find discriminant:

D=b^2-4ac=81-72=9

x=(-b±√D)/2a

x1=-6/6=-1

x2=-12/6=-2

one of the x values should be correct.

but why when I try to put values I get zero