write an equation of the line and interpret the slope
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Answer:
Step-by-step explanation:
Slope of this line will be= m= (600-200)/(1-5)
m = 400/-4 = -100
Eq of line will be:
(y-y1)=m(x-x1)
y-200=-100(x-5)
y-200+100x-500=0
100x+y-700 = 0
To write equation in slope-intercept form
y=mx+c
just seperate "y"
y=-100x+700
Hey there!
The answer to your question is [tex]y = -100x + 500[/tex]
To write this equation in slope-intercept form, first we must figure out the slope. We can do this using the formula
[tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]:
[tex]\frac{200-600}{5-1}[/tex]
[tex]\frac{-400}{4}[/tex]
[tex]-100[/tex]
Now, we have part of the equation: y = -100x + b. We have to find b, and we can do so by plugging in one of the points into the equation, like so:
[tex]600 = -100(1) + b[/tex]
[tex]600 = -100 + b[/tex]
[tex]500 = b[/tex]
Now, we have our equation:[tex]y = -100x + 500[/tex]
Hope it helps and have an amazing day!