Respuesta :

Answer:

Step-by-step explanation:

Slope of this line will be= m= (600-200)/(1-5)

m = 400/-4 = -100

Eq of line will be:

(y-y1)=m(x-x1)

y-200=-100(x-5)

y-200+100x-500=0

100x+y-700 = 0

To write equation in slope-intercept form

y=mx+c

just seperate "y"

y=-100x+700

Hey there!

The answer to your question is [tex]y = -100x + 500[/tex]

To write this equation in slope-intercept form, first we must figure out the slope. We can do this using the formula

[tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]:

[tex]\frac{200-600}{5-1}[/tex]

[tex]\frac{-400}{4}[/tex]

[tex]-100[/tex]

Now, we have part of the equation: y = -100x + b. We have to find b, and we can do so by plugging in one of the points into the equation, like so:

[tex]600 = -100(1) + b[/tex]

[tex]600 = -100 + b[/tex]

[tex]500 = b[/tex]

Now, we have our equation:[tex]y = -100x + 500[/tex]

Hope it helps and have an amazing day!

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