Question

100 points! I will mark brainliest! Only answers if you know it. Random answers WILL be reported

Answer 1

Answer:

2sqrt5

Step-by-step explanation:

We know that the shortest distance would be with drawing a perpendicular line through BC and A.

BC is y = -2x+1

Therefore a perpendicular line should have slope 1/2

y = 1/2x + b

-3 = 1/2*-3 + b

b = -3/2

y = -2x+1

y = 1/2x - 3/2

-2x+1 = 1/2x - 3/2

-4x+2 = x - 3

5 = 5x

x = 1

y = 1

now of course the graph shows that already, but we're just proving that again

The x-difference is 4, the y difference is 2, so 16+4 = 18, sqrt20 = 2sqrt5

Answer 2

Answer:

Solution given:

AB=

$AB = \sqrt{( - 3 +1 {)}^{2} + ( - 3 - 3 {)}^{2} } = 6.32units$

$AC= \sqrt{( - 3 - 1) ^{2} + ( - 3 + 1) {}^{2} } = 4.5$units

$AD= \sqrt{( - 3 - 0) {}^{2} + ( - 3 - 1) {}^{2} } = 5units$

so shortest distance=AC=4.5units