Question

3. International basketball competitions are played on a rectangular court where the length is 2x-2 and the width is x. If the perimeter of the court is 86 m. what are the dimensions of the court?

Answer 1

Answer:

• 28 m and 15 m

Step-by-step explanation:

Perimeter formula is:

• P = 2(l + w)

Given:

• l = 2x - 2 and w = x
• P = 86 m

Substitute and solve for x:

• 2(2x - 2 + x) = 86
• 3x - 2 = 43
• 3x = 45
• x = 15

Then find the values of l and w:

• l = 2*15 - 2 = 28 m
• w = 15 m

Answer 2

Answer:

length is 28m and width is 15m

Step-by-step explanation:

Let length = l

and width = b

According to the given condition,

l = 2b -2

Now,

Perimeter of a rectangle, P = 2(l+b)

According to question

P = 86

2(l+b) = 86

l + b = 43

2b -2 + b = 43

3b = 45

b =15

Therefore, l = 2x15 -2 = 28

So length is 28m and width is 15m