Question

WHOEVER ANSWERS CORRECTLY I WILL MARK BRAINLIEST!!

Answer 1

Answer:

Area = 342$cm^2$, Perimeter = 22.79 cm

Step-by-step explanation:

First, divide the shape into 3:

An arc, a square, and a triangle.

Dimensions of shapes:

Arc:

Degree = 40°

Arms = 4 cm

Square:

All sides are 4 cm

Triangle:

base = 3 cm

height = 4 cm

hypotenuse = 5 cm

To get perimeter:

Arc length = $\frac{40}{360} * (2*\pi * (4))$   (4 is the arm length ) = 2.7925 cm

Arc arm = 4 cm

Square sides (only two are outside) = 2 * 4 = 8 cm

Triangle (only hypotenuse and base are outside) = 5 + 3 = 8 cm

So total perimeter is 2.7925 + 4 + 8 + 8 = 22.79cm

To get area:

Arc area (the pizza shape) = $\frac{40}{2\pi } * \pi * (4)^{2}$   (4 is the arm length) = 320 $cm^{2}$

Square area  = side * side = 4 * 4 = 16 $cm^{2}$

Triangle =  (1/2) * base* height = (1/2) * 3 * 4 = 6$cm^{2}$

So total area is 320 + 16 + 6 = 342$cm^2$

Answer 2

Answer:

Area=27.58 cm^2

Perimeter =22.29cm

Step-by-step explanation:

The shape consists of a sector and a trapezium

For area= area of sector +area of trapezium

[θ/360*πr^2]+[1/2(a+b)h]

[40/360*3.14*4^2]+[1/2(4+7)4]

5.58+22

27.58cm^2

For perimeter = perimeter of sector +perimeter of square +perimeter of triangle

[θ/360*2πr]+[4s]+[1/2(a+b)]

[40/360*2*3.14*4]+[4*4]+[1/2(4+3)]

2.79+16+3.5

22.29cm