Question

3. The floor of building consists of 2000 tiles which are rhombus shaped and
each of its diagonals are 40 cm and 25 cm in length. Find the total cost of
polishing the floor, if the cost per m2 is Rs/5.​

Answer 1

Answer:

Total cost of polishing the floor is Rs/500.

Step-by-step explanation:

The floor consists of 2000 tiles which have the shape of a rhombus.

Area of rhombus = $\frac{d_{1} *d_{2} }{2}$

Where: $d_{1}$ and $d_{2}$ are the diagonals.

Given that:

$d_{1}$ = 40 cm = 0.4 m

$d_{2}$ = 25 cm = 0.25 m

Then,

Area of each tile = $\frac{0.4*0.25}{2}$

                     = $\frac{0.1}{2}$

                     = 0.05 $m^{2}$

Area of each tile is 0.05 $m^{2}$.

Since there are 2000 tiles on the floor of the building, then;

Total area covered by the tiles = 0.05 x 2000

                              = 100 $m^{2}$

The total cost of polishing the floor = 100 x Rs/5

                                = Rs/500