Question

100 points! Will mark brainliest! Only answer if u know it!

Answer 1

Answer:

y = - 2x - 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = $\frac{1}{2}$ x - 8 ← is in slope- intercept form

with slope m = $\frac{1}{2}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{\frac{1}{2} }$ = - 2, then

y = - 2x + c ← is the partial equation

To find c substitute (- 3, - 4) into the partial equation

- 4 = 6 + c ⇒ c = - 4 - 6 = - 10

y = - 2x - 10 ← equation of perpendicular line

Answer 2

Step-by-step explanation:

Hey there!

The 1st equation is;

y= 1/2 x-8.............(i)

Comparing the equation y= mx+c. We get;

Slope (m1) = 1/2

The equation of point which moves through point (-3,-4).

(y-y1) = m2 (x-x1). {Use one-point formula to find out the equation}

(y+4) = m2 (x+3)..………(ii)

Now, we need to find m2.

So, the condition of perpendicular lines: m1*m2= -1.

$\frac{1}{2} \times m2 = - 1$

$m2 = - 2$

Therefore, m2 = -2.

So, let's keep value of m2 in eqaution (ii).

y+4 = -2(X+3)

y+4 = -2x-6

y = -2x -10.

Therefore, the eqaution is y= -2x-10.

Hope it helps......