The boiling point of a solution : 100.1536 °C
Further explanation
Given
0.150 mole Al(NO₃)₃ in 0.500 kg water. kb= 0.512
Required
The boiling point
Solution
Colligative properties
ΔTb = Kb . m
m = molality = mol solute per kg solvent
m = 0.15 moles : 0.5 kg
m = 0.3
ΔTb = 0.512 x 0.3
ΔTb = 0.1536
ΔTb = Tb solution - Tb solvent (solvent=water, boiling point = 100 °C)
0.1536 = Tb solution - 100
Tb solution = 100.1536 °C
