Question

A canister containing air has a volume of 85 cm3 and a pressure of 1.45 atm when the tenoerature is 310 k. What is the pressure when the volune is increased to 180 cm3 and the temeprarje is reduced to 280 k?

Answer 1

Answer:

Pressure = 0.62 atm

Explanation:

$V_{1}$ = 85 $cm^{3}$, $P_{1}$ = 1.45 atm,  $T_{1}$ = 310 K, $V_{2}$ = 180 $cm^{3}$, $T_{2}$ = 280 K.

Applying the general gas law,

$\frac{P_{1} V_{1} }{T_{1} }$ = $\frac{P_{2} V_{2} }{T_{2} }$

$\frac{1.45*85}{310}$ = $\frac{P_{2}*180 }{280}$

$P_{2}$ = $\frac{1.45*85*280}{180*310}$

   = $\frac{34510}{55800}$

   = 0.62

$P_{2}$  = 0.62 atm

The pressure when the volume is increased and the temperature reduced to the given values is 0.62 atm.