Question

15 point question
The pressure P of a gas varies inversely as its
volume V and directly as the temperature T. A
certain gas has a pressure of 2.7 atm, a
volume of 3.6 L, and a temperature of 324 K.
If the volume of the gas is kept constant and
the temperature is increased to 396 K, what
will the new pressure be?

Answer 1

Answer:

The new pressure P₂  is 3.3 atm

Step-by-step explanation:

Pressure of gas = 2.7 atm

Volume = 3.6 L

Temperature = 324 K

Now we are given that  volume of the gas is kept constant.

Temperature is increased to 396 K

We need to find the pressure.

The formula used is: $\frac{P_1}{T_1}=\frac{P_2}{T_2}$

We have P₁ = 2.7

T₁ = 324 K

T₂ = 396 K

P₂ = ?

Putting values in the formula and finding P₂

$\frac{P_1}{T_1}=\frac{P_2}{T_2}\\\frac{2.7}{324}=\frac{P_2}{396}\\P_2=\frac{2.7}{324}\times 396\\P_2=0.0083 \times 396\\P_2=3.3$

So, the new pressure P₂  is 3.3 atm