Answer:
[tex]2.0\cdot 10^{-7}\:\mathrm{N}[/tex]
Explanation:
We can use Newton's Universal Law of Gravitation to solve this:
[tex]F=G\frac{m_1m_2}{r^2}[/tex], where [tex]F[/tex] is force, [tex]G[/tex] is gravitational constant [tex]6.67\cdot 10^{-11}[/tex], [tex]m_1[/tex]and [tex]m_2[/tex] represent the masses of both objects, and [tex]r[/tex] represents the distance between their center of masses.
Plugging in our given values, we have:
[tex]F=6.67\cdot 10^{-11}\frac{1700\cdot 1700}{30^2},\\F=\fbox{$2.0\cdot 10^{-7}\:\mathrm{N}$}[/tex](one significant figure).