a. t=0.553 s
b. vox(horizontal speed) = 3.62 m/s
Given
h = 1.5 m
x = 2 m
Required
a. time
b. vo=initial speed
Solution
Free fall motion
a. h = 1/2 gt²(vertical motion=h=voyt+1/2gt²⇒voy = 0)
[tex]\tt t=\sqrt{\dfrac{2h}{g} }[/tex]
t = √2h/g
t = √2.1.5/9.8
t=0.553 s
b. x=vox.t(horizontal motion)
[tex]\tt x=v_{ox}\times t[/tex]
vox=x/t
vox=2/0.553
vox=3.62 m/s