Question

PLEASE HELP WHICH ONE IS IT AND CAN YOU EXPLAN HOW YOU GOT THE ANSWERS TY!!!

In a titration, a 20 mL sample of NaOH(aq) was neutralized by 14.9 mL of 0.13 mol/L
H2SO4(aq). The concentration of the base is
A)8.7 mol/L
B)10.048 mol/L
C)0.19 mol/L
D)0.35 mol/L
/L

Answer 1

Answer:

C)0.19 mol/L .

Explanation:

Hello!

In this case, since the chemical reaction between sodium hydroxide and sulfuric acid is:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

Whereas a 1:2 mole ratio is seen between the acid and the base, we can write:

$2*M_{acid}V_{acid}=M_{base}V_{base}$

In such a way, we solve for the concentration of base and plug in to obtain:

$M_{base}=\frac{2*M_{acid}V_{acid}}{V_{base}} \\\\M_{base}=\frac{2*0.13mol/L*14.9mL}{20mL} \\\\M_{base}=0.19mol/L$

Thus, the answer is C)0.19 mol/L

Best regards!