Question

Megan walks 1100\,\text m1100m1100, start text, m, end text to the left in 330\,\text s330s330, start text, s, end text. What was her average speed in \dfrac{\text m}{\text s} s m ​ start fraction, start text, m, end text, divided by, start text, s, end text, end fraction?

Answer 1

Answer:

v = 3.34 m/s

Explanation:

Given that,

Distance, d = 1100 m

Time, t = 330 s

We need to find the average speed of the Megan. It is equal to the total distance divided by total time taken.

$v=\dfrac{1100\ m}{330\ s}\\\\v=3.34\ m/s$

So, the average speed of Megan is 3.34 m/s.