please help will mark brainliest

Answer:
[tex]m\angle N=57^{\circ}[/tex]
Step-by-step explanation:
From the isosceles-base theorem, the measure of the angles adjacent to the pair of congruent sides of the triangle are equal. Since the problem declares [tex]LM\cong LN[/tex], the remaining unknown angles are equal ([tex]m\angle N=m\angle M[/tex]). The sum of the interior angles of a triangle always add up to [tex]180^{\circ}$[/tex].
Therefore:
[tex]m\angle N\cdot 2+66=180,\\m\angle N\cdot 2=114,\\m\angle N=\fbox{$57^{\circ}$}[/tex] .
Answer:
LMN is rectangle in L so LMN= 180° ; ML=66°;N=? N= 180°- 66°=114=114/2= 57° so N=57°
Step-by-step explanation:
When the angle at the top is close to 0 °, the two of the base get less than 180 °, or less than 90 ° for each. If the angle at the top is 60 °, the other two are: 180 - 60 = 120 °, and each is: 120/2 = 60 °.