Question

Select the correct answer.
What are the values of x and y if this equation is true?
22(X+yi)+(28+4i)=72-62i)

Answer 1

Answer:

$\huge\boxed{x=2\ and\ y=-3}$

Step-by-step explanation:

$22(x+yi)+(28+4i)=72-62i\\\\22x+22yi+28+4i=72-62i\\\\(22x+28)+(22y+4)i=72-62i\Rightarrow22x+28=72\ \wedge\ 22y+4=-62\\\\22x+28=72\qquad|\text{subtract 28 from both sides}\\22x=44\qquad|\text{divide both sides by 22}\\\boxed{x=2}\\\\22y+4=-62\qquad|\text{subtract 4 from both sides}\\22y=-66\qquad|\text{divide both sides by 22}\\\boxed{y=-3}$