Answer:
[tex]T =99.94[/tex]
Explanation:
From the question we are told that
The distance between the poles is [tex]d = 20 \ m[/tex]
The mass is [tex]m = 2 \ kg[/tex]
The sag distance [tex]=5m[/tex]
Generally the tension in the rope is mathematically represented as as
[tex]T =\frac{mg}{2sin(\theta)}[/tex]
where [tex]\theta =arctan(\frac{1}{5})[/tex]
[tex]T =\frac{m*9.8}{2sin(tan^-1(\frac{1}{5})}\\[/tex]
[tex]T =99.94[/tex]
the tension on the line is 99.94