Question

If the equal tensions T in the pulley cable are 300 N, express in vector notation the force R exerted on the pulley by the two tensions. Determine the magnitude of R.

Answer 1

Answer:

$R=519.61N$

Explanation:

From the question we are told that

Tension T on a cable are T=300N

Generally the tensions on a pulley is

       $\sum f_x=T+T*cos(\theta)$

Therefore

      $\sum f_x=300+300*cos(60)$

      $\sum f_x=300 *1.5$

      $\sum f_x=450N$

Hence

      $T*sin(60) = 259.81N$

     $R= 450\=i +259.81\=i$

     $R=\sqrt{450^2+259.8^2}$

     $R=519.61N$