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  • 31-12-2020
  • Mathematics
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If $m \Diamond n = (m^2 - n) \div n$ for all real numbers $m$ and $n$, where $n \neq 0$, what is the value of $6 \Diamond 3$?

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LammettHash
LammettHash LammettHash
  • 31-12-2020

By definition of ◇, you have

6 ◇ 3 = (6² - 3)/3 = (36 - 3)/3 = 33/3 = 11

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