Question

1. A 146 kg cubic tiger began with an initial velocity of -22 m/s [N] and, while moving away from the origin, accelerated at -0.43 m/s² [N] and moved -407 m [N]. What was the final velocity of the tiger?

Answer 1

Answer:

v = 28.87 m/s

Explanation:

Given that,

Mass of a cubic tiger, m = 146 kg

Initial velocity, u = -22 m/s

Acceleration, a = -0.43 m/s²

Distance moved, s = -407 m

We need to find the final velocity of the tiger. Using third equation of motion to find it. Let v is the final velocity of the tiger.

$v^2-u^2=2as\\\\v^2=(-22)^2+2\times (-0.43)\times (-407)\\\\=28.87\ m/s$

So, the final velocity of the tiger is 28.87 m/s.