Answer:
[tex](x,y) = (\¾, \frac{5}{2})[/tex]
Step-by-step explanation:
Given
[tex]Ratio = 1 :3[/tex]
[tex]A = (-3, 2)[/tex]
[tex]B = (12 , 4)[/tex]
Required
Determine the coordinates at the given ratio
This is calculated using the following formula
[tex](x,y) = \frac{mx_2 + nx_1}{ m + n}, \frac{my_2 + ny_1}{m + n}[/tex]
Where:
[tex]m : n = 1 : 3[/tex]
Substitute values for x1, x2, y1, y2, m and n
[tex](x,y) = (\frac{1 * 12 + 3 * -3}{1 + 3},\frac{1 * 4 + 3 * 2}{1 + 3})[/tex]
[tex](x,y) = (\frac{12-9}{4},\frac{4 + 6}{4})[/tex]
[tex](x,y) = (\¾,\frac{10}{4})[/tex]
The coordinates is at point: [tex](\¾, \frac{5}{2})[/tex]