Question

A car slows from 22 m/s to 3.0 m/s at a constant rate of 2.1 m/s2. How many seconds are required before the car is traveling at a forward velocity of 3.0 m/s?

Answer 1

Answer: 9.05 s

     

Explanation: v = u +at

v = 3 m/s

u = 22 m/s

Deceleration = 2.1 m/s^2

∴ 3 = 22 - 2.1 ( t )

∴ t = 9 .05 s