Question

What is the molar mass of 81.50 g of gas
exerting a pressure of 1.75 atm on the
walls of a 4.92 L container at 307 K?

Answer 1

The molar mass  of gas = 238.29 g/mol

Further explanation

Given

mass = 81.5 g

P=1.75 atm

V=4.92 L

T=307 K

Required

molar mass

Solution

The gas equation can be written  

$\large{\boxed{\bold{PV=nRT}}$

$\tt n=\dfrac{mass}{molar~mass}$

So the equation becomes :

$\tt Molar~mass=\dfrac{mRT}{PV}$

Input the value :

$\tt M=\dfrac{81.5\times 0.082\times 307}{1.75\times 4.92}\\\\M=238.29~g/mol$

Answer 2

Answer:

239

Explanation: