Given:
The vertices of ΔJKL are J(-3, -2), K(1, 4), and L(4, 2).
To find:
The coordinate pairs of vertices of [tex]D_5(\Delta JKL)[/tex].
Solution:
We know that, [tex]D_5(\Delta JKL)[/tex] means triangle JKL dilated by scale factor 5 with origin as center of dilation.
If a figure is dilated by factor k and origin is the center of dilation, then
[tex](x,y)\to (kx,ky)[/tex]
From the given problem, the rule of dilation is
[tex](x,y)\to (5x,5y)[/tex]
Now,
[tex]J(-3,-2)\to J'(5(-3),5(-2))=J'(-15,-10)[/tex]
[tex]K(1,4)\to K'(5(1),5(4))=K'(5,20)[/tex]
[tex]L(4,2)\to L'(5(4),5(2))=L'(20,10)[/tex]
Therefore, the coordinate pairs of vertices of [tex]D_5(\Delta JKL)[/tex] are J'(-15,-10), K'(5,20) and L'(20,10).