Question

How many moles of O, will occupy 1.00 L at a temper-
ature of -118°C and a pressure of 49.77 atm?

Answer 1

Moles of O₂ = 3.92

Further explanation

Given

V=1 L

T=-118 °C + 273 = 155 K

P = 49.77 atm

Required

moles of O₂

Solution

the gas equation can be written  

$\large {\boxed {\bold {PV = nRT}}}$

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

Input the value :

n= PV/RT

$\tt n=\dfrac{49.77~atm\times 1~L}{0.082\times 155}=3.92~moles$