Answer:
[tex]5110, 5111, 5112[/tex]
Step-by-step explanation:
Let [tex]x=[/tex] first consecutive number
[tex]x + (x+1)+(x+2) = 15333[/tex] ([tex]x[/tex] is the first number, [tex]x+1[/tex] would be the second consecutive number of the sequence, and [tex]x+2[/tex] would be the third)
[tex]3x + 3 = 15333[/tex]
[tex]3x = 15330[/tex]
[tex]x = 5110[/tex]
[tex]x+1 = 5110+1[/tex]
[tex]= 5111[/tex]
[tex]x+2 = 5110 + 2[/tex]
[tex]= 5112[/tex]
[tex]\therefore[/tex] the consecutive numbers that sum up to [tex]15333[/tex] are [tex]5110, 5111,[/tex] and [tex]5112[/tex]
Hope this helps :)