What is the area of a hexagon with a side length of 10? it also has a rectangle in it with other measurements but the question is asking for the area of the hectagon.

Respuesta :

Answer:

there is a formula for a hexagon ..  it's

Area = 3[tex]\sqrt{3\\}[/tex]/2 * [tex]length^{2}[/tex]

where length is the length of one side, assuming all sides are equal

Step-by-step explanation:

3*[tex]\sqrt{3}[/tex]/2= 7.348469228.........

since the length is 10...   the length squared is 100

then the total area of the hexagon is 734.8469228...... [tex]units^{2}[/tex].. what ever they are

if you want to work with some concepts.. you could also say that a hexagon is just a box with the corners cut off and the triangles that are missing are the equilateral right triangles with a hypotenuse of 10 .  and since 2 pieces of those triangles make a square.. you can subtract two squares of that size from the bigger box that the hexagon fits into.  this is a long way to figure this out but might be good for trigonometry practice   :)

it will also be 734.8463288.....  see if you can work that out :)

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