Respuesta :

(2x + I) (2x-I) = 4x^2 + 1

Using the complex arithmetic rule:

(A + bi)(a-bi) = a^2 + b^2

A would be the 2x and b would be the i

So you would have:

(2x)^2 + (i)^2

(2x)^2 = 2x times 2x = 4x^2

i ^2 = 1

Final answer is 4x^2 + 1

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