500 mL of He at 98 kPa expands to 750 mL. Find P2.
P₂ = 65.3 kPa
Further explanation
Given
V₁=500 ml
P₁=98 kPa
V₂=750 ml
Required
P₂
Solution
Boyle's Law
At a constant temperature, the gas volume is inversely proportional to the pressure applied
[tex]\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}[/tex]
Input the value :
[tex]\tt P_2=\dfrac{P_1.V_1}{V_2}\\\\P_1=\dfrac{98.500}{750}\\\\P_2=65.3~kPa[/tex]
