Respuesta :

Answer:

[tex]x = \frac{ - 3}{2} \: or \: \frac{1}{3} [/tex]

Step-by-step explanation:

[tex]7 {x}^{2} + 10x - 3 = {x}^{2} + 3x[/tex]

[tex] = > 7 {x}^{2} - {x}^{2} + 10x - 3x -3 = 0[/tex]

[tex] = > 6 {x}^{2} + 7x - 3 = 0[/tex]

[tex] = > 6 {x}^{2} + 9x - 2x - 3 = 0[/tex]

[tex] = > 3x(2x + 3) - 1(2x + 3) = 0[/tex]

[tex] = > (2x + 3)(3x - 1) = 0[/tex]

Here x will have 2 values.

1) [tex]2x + 3 = 0[/tex]

[tex] = > 2x = - 3[/tex]

[tex] = > x = \frac{ - 3}{2} [/tex]

2)[tex]3x - 1 = 0[/tex]

[tex] = > 3x = 1[/tex]

[tex] = > x = \frac{1}{3} [/tex]

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