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Answer:
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Step-by-step explanation
In an auditorium, there are 21 seats in the first row and 29 seats in the second row. The number of seats in a row continues to increase by 8 with each additional row. How would you find the 100th row?
We can take this as an arithmetic sequence, as the seats in next row is calculated by adding 8 to previous row
So here common difference will be 8
the first term is 21
the arithmetic sequence is given by:
Putting the values of a1 and d
for 100th row,
Putting n=100
3. The sequence 6, 18, 54, 162, … shows the number of pushups Kendall did each week, starting with her first week of exercising.
Give the rule you would use to find the 20th week.
Given sequence is:
6, 18, 54, 162, …
we can see that the common difference is not same so we will find the common ratio
The given sequence is a geometric sequence as are the same for consecutive terms
The geometric sequence is given by:
Hence,
2. Seats in 100th Row = 813
3. Rule is:
Keywords: Sequence, ratio
Answer:
see explanation
Step-by-step explanation:
The sequence is
22, 28, 34, ....
Since there is a common difference of 6 the sequence is arithmetic with n th term
[tex]a_{n}[/tex] = a₁ + (n - 1)d
a₁ is the first term and d the common difference
Here a₁ = 22 and d = 6, then
[tex]a_{n}[/tex] = 22 + 6(n - 1) = 22 + 6n - 6 = 6n + 16
Equate to 100 and solve for n
6n + 16 = 100 ( subtract 16 from both sides )
6n = 84 ( divide both sides by 6 )
n = 14
Thus the 14 th row has 100 seats