Question

At a sports event, the car starts from iosi, in 5.0 siis acceleration is 5.
Calculate the distance travelled by ban
100 m
25 m
63 m
O bag 6.
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werissa 13​

Answer 1

Question:

At a sports event, the car starts from rest. in 5.0 s its acceleration is 5.0 m/s2.  Calculate the distance travelled by car.

Answer:

62.5 metres

Explanation:

Given

$u = 0$ -- Initial Velocity

$a = 5.0m/s^2$ --- acceleration

$t =5.0s$ -- time

Required

Calculate the distance

This question will be solved using the following equation of motion

$S = ut + \frac{1}{2}at^2$

Where S represents the distance

Substitute values for u, t and a

$S = 0 * 5.0 + \frac{1}{2} * 5.0 * 5.0^2$

$S = 0 + \frac{1}{2} * 5.0 * 25.0$

$S = \frac{1}{2} * 5.0 * 25.0$

$S = \frac{1}{2} * 125.0$

$S = 62.5m$

Hence, the distance travelled is 62.5m