Answer:
The speed with which a rock would have to be thrown to put it in 234 Ida's orbit, near its surface is approximately 12.917 m/s
Explanation:
The given parameters are;
The mass of Ida, M = 4 × 10¹⁶ kg
The radius of 234 Ida, r = 16 km = 16,000 m
The speed, v, required to put a rock in 234 Ida's orbit near its surface is given by the orbital velocity equation as follows;
[tex]v = \sqrt{{\dfrac{G \times M}{r} } }[/tex]
Where;
G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²
Substituting the known values gives;
[tex]v = \sqrt{{\dfrac{6.67408 \times 10^{-11} \times 4 \times 10^{16}}{16,000} } } \approx 12.917[/tex]
Therefore, the speed required to put a rock in 234 Ida's orbit near its surface = v ≈ 12.917 m.