Question

A cylinder of length 2.85 m, radius 0.440 m, and mass 14.7 kg is rotated at an angular speed of 4.10 rad/s around an axis parallel to the length of the cylinder and through its center. Find the magnitude of the cylinder's angular momentum.

Answer 1

Answer:

70.45 kg.m^2/s

Explanation:

Mass of the rod = M = 14.7 kg

Length of the rod = L = 2.85 m

Moment of inertia of the rod about one of its ends = I

$I= \frac{ML^{2}}{3}$

$I= \frac{(14.7)(4.10)^{2}}{3}$

I = 82.369 kg.m^2

Angular speed of the rod = ω = 3.60 rad/s

Magnitude of the rod's angular momentum = L

L = Iω

L = (82.369)(3.60)

L = 70.45 kg.m^2/s

Magnitude of the rod's angular momentum = 70.45 kg.m^2/s