Answer:
Both vehicles experience the same change in momentum
Explanation:
Let m represent the mass of the vehicle, and 2m represent the mass of the large truck, and let v represent their initial speed, we have;
The total initial momentum, [tex]p_i[/tex] given as follows;
[tex]p_i[/tex] = 2·m·v - m·v = m·v
The total final momentum, [tex]p_f[/tex] = (2·m + m) × [tex]v_f[/tex]
By the principle of conservation of linear momentum, the total initial momentum = The total final momentum
m·v = (2·m + m) × [tex]v_f[/tex]
m·v = 3·m·[tex]v_f[/tex]
∴ v = 3 × [tex]v_f[/tex]
[tex]v_f[/tex] = v/3
The change in the momentum for the large truck = 2·m·v - 2·m·[tex]v_f[/tex]
Therefore;
The change in the momentum for the large truck = 2·m·v - 2·m·v/3 = 2·m·(v - v/3)
The change in the momentum for the large truck = 2·m·(v - v/3) = 2·m·2·v/3 = 4·m·v/3
The change in the momentum for the car = m·v - m·(-[tex]v_f[/tex]) = m·v - m·(-v)/3 = m·v + m·(v)/3 = 4·m·v/3
Therefore, the change in the momentum for the large truck = The change in the momentum for the car and both vehicles experience the same change in momentum.