Answer:
The coordinates of the vertex are (-1,-4).
Step-by-step explanation:
Equation of the Quadratic Function
The vertex form of the quadratic function has the following equation:
[tex]y-k=a(x-h)^2[/tex]
Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.
We are given the function:
[tex]y=x^2+2x-3[/tex]
We must transform the equation above by completing squares:
The first two terms can be completed to be the square of a binomial. Recall the identity:
[tex]x^2+2xy+y^2=(x+y)^2[/tex]
Thus if we add and subtract 1:
[tex]y=(x^2+2x+1)-3-1[/tex]
Operating:
[tex]y=(x^2+2x+1)-4[/tex]
The trinomial in parentheses is a perfect square:
[tex]y=(x+1)^2-4[/tex]
Adding 4:
[tex]y+4=(x+1)^2[/tex]
Comparing with the vertex form of the quadratic function, we have the vertex (-1,-4).
The coordinates of the vertex are (-1,-4).