Answer:
2.4 dm-3
Explanation:
Equation of the reaction;
2HCl(aq) + Ba(OH)2(aq) -------> BaCl2(aq) + 2 H2O(l)
Volume of acid VA = ??
Concentration of acid CA = 0.25 moldm-3
Volume of base VB = 2.0 dm^3
Concentration of base CB = 0.15 moldm-3
Number of moles of acid NA = 2
Number of moles of base NB = 1
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
VA = CBVBNA/CANB
VA = 0.15 * 2 * 2/0.25 *1
VA = 2.4 dm-3
