The balanced reaction is
4 Al + 3 O₂ → 2 Al₂O₃
so that for every 4 moles of Al and 3 moles of O2, you end up with 2 moles of Al₂O₃.
• Al has molar mass ≈ 26.982 g/mol
• O has molar mass ≈ 15.999 g/mol
• Al₂O₃ thus has molar mass ≈ 101.961 g/mol
You start with 5.4 kg = 5,400 g of Al, or
(5.4 kg Al) • (1/26.982 mol/g) ≈ 200.133 mol Al
Al₂O₃ is produced in a ratio of 2 moles to every 4 moles of Al, so you end up with about 100.067 mol Al₂O₃, which has a mass of
(100.067 mol Al₂O₃) • (101.961 g/mol) ≈ 10,202 g = 10.2 kg
so the answer is C.