Respuesta :

Solution :

[tex] \sf \dfrac{6x+4}{3} = \dfrac{5x-5}{8}[/tex]

By cross multiply, we get

[tex] \sf : \implies (6x+4) \times 8 = (5x-5) \times 3[/tex]

[tex] \sf : \implies 48x+32 = 15x-15[/tex]

[tex] \sf : \implies 48x+32 - 15x + 15= 0[/tex]

[tex] \sf : \implies 33x + 47 = 0[/tex]

[tex] \sf : \implies 33x = -47[/tex]

[tex] \sf : \implies x = \dfrac{- 47}{33}[/tex]

Therefore, answer is [tex] \sf x = \dfrac{- 47}{33}[/tex]

pi314

ANSWER:

x=-47/33

EXPLANATION:

[tex]\frac{6x+4}{3} =\frac{5x-5}{8} \\\\24(\frac{6x+4}{3} =\frac{5x-5}{8})\\\\48x+32=15x-15\\\\48x+32-32=15x-15-32\\\\48x-15x=-47+15x-15x\\\\33x=-47\\\\x=-\frac{47}{33}x[/tex]

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