Answer:
234 90Th → 0 -1e + 234 91Pa Explanation:
Given that :
Thorium 234 decays by beta emission Beta emission = 0, - 1 e
234 90Th → 0 -1e + 234 91Pa Hence, when Thorium 234 90 undergoes a beta Decay ; mass number remains the same at 234 while atomic number increases by 1, becoming (90 + 1) = 91 to form a protactinium nuclide.
