How do I solve this?

Answer:
The given parameters are;
[tex]\overline{PS}[/tex] ≅ [tex]\overline{PT}[/tex], ∠PRS ≅ ∠PRT
To prove that ΔPRS ≅ ΔPRT
A two column proof is given as follows;
Statement [tex]{}[/tex] Reason
∠PRS and ∠PRT are ≅ [tex]{}[/tex] Given
∠PRS and ∠PRT are [tex]{}[/tex] ∡ that form a linear pair are supplementary
supplementary angles
∠PRS and ∠PRT are right ∡ [tex]{}[/tex] Two ≅ and supplementary angles are right ∡
ΔPRS and ΔPRT are right Δ [tex]{}[/tex] Triangle with one angle = 90°
[tex]\overline {PS}[/tex] ≅ [tex]\overline {PT}[/tex] [tex]{}[/tex] Given
[tex]\overline {PR}[/tex] ≅ [tex]\overline {PR}[/tex] [tex]{}[/tex] Reflective property
ΔPRS ≅ ΔPRT [tex]{}[/tex] By hypotenuse leg postulate.
Step-by-step explanation:
The given parameters are;
[tex]\overline{PS}[/tex] ≅ [tex]\overline{PT}[/tex], ∠PRS ≅ ∠PRT
To prove that ΔPRS ≅ ΔPRT
A two column proof is given as follows;
Statement [tex]{}[/tex] Reason
∠PRS and ∠PRT are congruent [tex]{}[/tex] Given
2) ∠PRS and ∠PRT are supplementary angles by angles that form a linear pair are supplementary
3) ∠PRS and ∠PRT are right angles by [tex]{}[/tex] Two congruent angles which are also supplementary (sum up to 180°) are two 90° angles
4) ΔPRS and ΔPRT are right triangles [tex]{}[/tex] Triangle with one angle = 90°
[tex]\overline {PS}[/tex] ≅ [tex]\overline {PT}[/tex] [tex]{}[/tex] Given
[tex]\overline {PR}[/tex] ≅ [tex]\overline {PR}[/tex] [tex]{}[/tex] Reflective property
ΔPRS ≅ ΔPRT [tex]{}[/tex] By hypotenuse leg postulate for the congruency of two right triangles.