Answer:
The height of the cliff is 78.4 m
Explanation:
Horizontal Launch Motion
When an object is thrown horizontally with a speed v from a height h, it describes a curved path exclusively ruled by gravity until it hits the ground.
The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:
[tex]v_x=v_o[/tex]
The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:
[tex]v_y=g.t[/tex]
Where g is the acceleration of gravity.
The maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
If the horizontal distance and the speed are known, we can solve the equation above for h:
[tex]\displaystyle h=\frac{d^2g}{2v^2}[/tex]
The car leaves a cliff at a horizontal speed of v=15 m/s and hits the ground d=60 m from the shoreline. Thus the height of the cliff is:
[tex]\displaystyle h=\frac{60^2*9.8}{2*15^2}[/tex]
Calculating:
h = 78.4 m
The height of the cliff is 78.4 m
