Respuesta :
Answer: the variance of the winnings from this raffle is 162.7
Step-by-step explanation:
Given that;
X P( X=x ) xP(x) x²P(X)
10 0.095 0.95 9.5
20 0.045 0.9 18
50 0.020 1.0 50
100 0.010 1.0 100
0 0.830 0.0 0
TOTAL 1 3.85 177.5
therefore the variance will be;
Var(X) = [ ∑(x²) - [∑(X)]² ]
so we substitute
Var(X) = [ 177.5 - (3.85)² ]
= [ 177.5 - 14.8225 ]
= 162.6775 ≈ 162.7
therefore the variance of the winnings from this raffle is 162.7
The variance of the winnings from this raffle is 162.7
Calculation of the variance:
Since
X P( X=x ) xP(x) x²P(X)
10 0.095 0.95 9.5
20 0.045 0.9 18
50 0.020 1.0 50
100 0.010 1.0 100
0 0.830 0.0 0
TOTAL 1 3.85 177.5
Now the variance should be
Var(X) = [ 177.5 - (3.85)² ]
= [ 177.5 - 14.8225 ]
= 162.6775
≈ 162.7
therefore the variance of the winnings from this raffle is 162.7
Learn more about variance here: https://brainly.com/question/24138432