3.01 × 10²³ atoms C
Chemistry
Atomic Structure
Math
Pre-Algebra
Order of Operations: BPEMDAS
Step 1: Define
6.00 g C
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of C - 12.01 g/mol
Step 3: Convert
[tex]6.00 \ g \ C(\frac{1 \ mol \ C}{12.01 \ g \ C} )(\frac{6.022 \cdot 10^{23} \ atoms \ C}{1 \ mol \ C} )[/tex] = 3.00849 × 10²³ atoms C
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
3.00849 × 10²³ atoms C ≈ 3.01 × 10²³ atoms C