Question

Write an euqation of a line that is perpendicular to y=1/2x+3 and passes through the point (10,-5)

Answer 1

Step-by-step explanation:

Slope of the perpendicular line = (-1)/(1/2) = -2.

y = -2x + c. When x = 10, y = -5.

=> (-5) = -2(10) + c, c = 15.

Hence the equation of the line is y = -2x + 15.