Qc < Kc, the reaction proceeds from left to right to reach equilibrium
Given
K = 50.2 at 445°C
[H2] = [I2] = [HI] = 1.75 × 10⁻³ M At 445ºC
Reaction
H2(g) + I2(g) ⇔2HI(g)
Required
Qc
Solution
Qc for the reaction
[tex]\tt Qc=\dfrac{[HI]^2}{[I_2][H_2]}\\\\Qc=\dfrac{(1.75.10^{-3})^2}{1.75.10^{-3}\times 1.75\.10^{-3}}=1[/tex]
Qc < Kc ⇒ reaction from left(reactants) to right (products) (the reaction will shift on the right) until it reaches equilibrium (Qc = Kc)