Usha thinks that the area of the development will be greater than the total area of 50 football pitches.
Usha knows
• a football pitch is rectangular 100m by 50m
• 1 mile = 1600m.

Respuesta :

Answer:

Usha is correct

Step-by-step explanation:

See attachment

Given

Dimension of the development

[tex]Height = \frac{1}{2}\ mile[/tex]

[tex]Base = \frac{1}{2}\ mile[/tex]

Dimension of a football field

[tex]Length = 100m[/tex]

[tex]Width = 50m[/tex]

First, we calculate the area of the development.

Because it is triangular in shape, the area is:

[tex]Area = \frac{1}{2} * Height * Base[/tex]

[tex]Area = \frac{1}{2} * \frac{1}{2}mile * \frac{1}{2}mile[/tex]

Convert mile to meter

[tex]Area = \frac{1}{2} * \frac{1}{2}* 1600m * \frac{1}{2} * 1600m[/tex]

[tex]Area = \frac{1}{2} * 800m * 800m[/tex]

[tex]Area = 400m * 800m[/tex]

[tex]Area = 320000m^2[/tex]

The area of 50 football pitch is then calculated as:

[tex]Area = 50 * Length * Width[/tex]

[tex]Area = 50 * 100m * 50m[/tex]

[tex]Area = 250000m^2[/tex]

By comparison:

[tex]320000 > 250000[/tex]

Hence, Usha's thought is correct

Ver imagen MrRoyal
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