Answer:
Usha is correct
Step-by-step explanation:
See attachment
Given
Dimension of the development
[tex]Height = \frac{1}{2}\ mile[/tex]
[tex]Base = \frac{1}{2}\ mile[/tex]
Dimension of a football field
[tex]Length = 100m[/tex]
[tex]Width = 50m[/tex]
First, we calculate the area of the development.
Because it is triangular in shape, the area is:
[tex]Area = \frac{1}{2} * Height * Base[/tex]
[tex]Area = \frac{1}{2} * \frac{1}{2}mile * \frac{1}{2}mile[/tex]
Convert mile to meter
[tex]Area = \frac{1}{2} * \frac{1}{2}* 1600m * \frac{1}{2} * 1600m[/tex]
[tex]Area = \frac{1}{2} * 800m * 800m[/tex]
[tex]Area = 400m * 800m[/tex]
[tex]Area = 320000m^2[/tex]
The area of 50 football pitch is then calculated as:
[tex]Area = 50 * Length * Width[/tex]
[tex]Area = 50 * 100m * 50m[/tex]
[tex]Area = 250000m^2[/tex]
By comparison:
[tex]320000 > 250000[/tex]
Hence, Usha's thought is correct